0.2x^2-x-4.1=0

Solution for 0.2x^2-x-4.1=0 equation:

0.2x^2-x-4.1=0

We add all the numbers together, and all the variables

0.2x^2-1x-4.1=0

a = 0.2; b = -1; c = -4.1;
Δ = b2-4ac
Δ = -12-4·0.2·(-4.1)
Δ = 4.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{4.28}}{2*0.2}=\frac{1-\sqrt{4.28}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{4.28}}{2*0.2}=\frac{1+\sqrt{4.28}}{0.4}
$